Min and Emily had a total of 154 coins. Emily gave ¹₄ of her coins to Min. In return, Min gave ¹₈ of the total number of coins that she had to Emily. In the end, each girl had the same number of coins. How many coins did Min have at first?

	Min	Emily	Total
Before 1	?	4 u	154
Change 1	+ 1 u	- 1 u
After 1	88	3 u	154
Before 2	8 p	3 u	154
Change 2	- 1 p	+ 1 p
After 2	7 p (77)	77	154

Since Emily gave some coins to Min and Min then gave some coins to Emily, it is an internal transfer of coins between the two girls. So, the total number of coins remains unchanged.

Number of coins that Emily and Min each had in the end is the same.

Number of coins that Min had in the end
= 154 ÷ 2
= 77

Number of coins that Min had in the end = 7 p

7 p = 77

1 p = 77 ÷ 7 = 11

Number of coins that Min had after receiving some coins from Emily
= 8 p
= 8 x 11
= 88

Number of coins that Emily had after giving to Min
= 154 - 88
= 66

3 u = 66

1 u = 66 ÷ 3 = 22

Number of coins that Emily had at first
= 4 u
= 4 x 22
= 88

Number of coins that Min had at first
= 154 - 88
= 66

Answer(s): 66