Shiyun and Betty had a total of 80 stickers. Betty gave
16 of her stickers to Shiyun. In return, Shiyun gave
15 of the total number of stickers that she had to Betty. In the end, each girl had the same number of stickers. How many stickers did Shiyun have at first?
|
Shiyun |
Betty |
Total |
Before 1 |
? |
6 u |
80 |
Change 1 |
+ 1 u |
- 1 u |
|
After 1 |
50 |
5 u |
80 |
Before 2 |
5 p |
5 u |
80 |
Change 2 |
- 1 p |
+ 1 p |
|
After 2 |
4 p (40) |
40 |
80 |
Since Betty gave some stickers to Shiyun and Shiyun then gave some stickers to Betty, it is an internal transfer of stickers between the two girls. So, the total number of stickers remains unchanged.
Number of stickers that Betty and Shiyun each had in the end is the same.
Number of stickers that Shiyun had in the end
= 80 ÷ 2
= 40
Number of stickers that Shiyun had in the end = 4 p
4 p = 40
1 p = 40 ÷ 4 = 10
Number of stickers that Shiyun had after receiving some stickers from Betty
= 5 p
= 5 x 10
= 50
Number of stickers that Betty had after giving to Shiyun
= 80 - 50
= 30
5 u = 30
1 u = 30 ÷ 5 = 6
Number of stickers that Betty had at first
= 6 u
= 6 x 6
= 36
Number of stickers that Shiyun had at first
= 80 - 36
= 44
Answer(s): 44