Lucy and Yen had a total of 140 coins. Yen gave
16 of her coins to Lucy. In return, Lucy gave
18 of the total number of coins that she had to Yen. In the end, each girl had the same number of coins. How many coins did Lucy have at first?
|
Lucy |
Yen |
Total |
Before 1 |
? |
6 u |
140 |
Change 1 |
+ 1 u |
- 1 u |
|
After 1 |
80 |
5 u |
140 |
Before 2 |
8 p |
5 u |
140 |
Change 2 |
- 1 p |
+ 1 p |
|
After 2 |
7 p (70) |
70 |
140 |
Since Yen gave some coins to Lucy and Lucy then gave some coins to Yen, it is an internal transfer of coins between the two girls. So, the total number of coins remains unchanged.
Number of coins that Yen and Lucy each had in the end is the same.
Number of coins that Lucy had in the end
= 140 ÷ 2
= 70
Number of coins that Lucy had in the end = 7 p
7 p = 70
1 p = 70 ÷ 7 = 10
Number of coins that Lucy had after receiving some coins from Yen
= 8 p
= 8 x 10
= 80
Number of coins that Yen had after giving to Lucy
= 140 - 80
= 60
5 u = 60
1 u = 60 ÷ 5 = 12
Number of coins that Yen had at first
= 6 u
= 6 x 12
= 72
Number of coins that Lucy had at first
= 140 - 72
= 68
Answer(s): 68