Raeann and Linda had a total of 96 stamps. Linda gave
13 of her stamps to Raeann. In return, Raeann gave
15 of the total number of stamps that she had to Linda. In the end, each girl had the same number of stamps. How many stamps did Raeann have at first?
|
Raeann |
Linda |
Total |
Before 1 |
? |
3 u |
96 |
Change 1 |
+ 1 u |
- 1 u |
|
After 1 |
60 |
2 u |
96 |
Before 2 |
5 p |
2 u |
96 |
Change 2 |
- 1 p |
+ 1 p |
|
After 2 |
4 p (48) |
48 |
96 |
Since Linda gave some stamps to Raeann and Raeann then gave some stamps to Linda, it is an internal transfer of stamps between the two girls. So, the total number of stamps remains unchanged.
Number of stamps that Linda and Raeann each had in the end is the same.
Number of stamps that Raeann had in the end
= 96 ÷ 2
= 48
Number of stamps that Raeann had in the end = 4 p
4 p = 48
1 p = 48 ÷ 4 = 12
Number of stamps that Raeann had after receiving some stamps from Linda
= 5 p
= 5 x 12
= 60
Number of stamps that Linda had after giving to Raeann
= 96 - 60
= 36
2 u = 36
1 u = 36 ÷ 2 = 18
Number of stamps that Linda had at first
= 3 u
= 3 x 18
= 54
Number of stamps that Raeann had at first
= 96 - 54
= 42
Answer(s): 42