Kimberly and Zoe had a total of 96 stickers. Zoe gave
13 of her stickers to Kimberly. In return, Kimberly gave
15 of the total number of stickers that she had to Zoe. In the end, each girl had the same number of stickers. How many stickers did Kimberly have at first?
|
Kimberly |
Zoe |
Total |
Before 1 |
? |
3 u |
96 |
Change 1 |
+ 1 u |
- 1 u |
|
After 1 |
60 |
2 u |
96 |
Before 2 |
5 p |
2 u |
96 |
Change 2 |
- 1 p |
+ 1 p |
|
After 2 |
4 p (48) |
48 |
96 |
Since Zoe gave some stickers to Kimberly and Kimberly then gave some stickers to Zoe, it is an internal transfer of stickers between the two girls. So, the total number of stickers remains unchanged.
Number of stickers that Zoe and Kimberly each had in the end is the same.
Number of stickers that Kimberly had in the end
= 96 ÷ 2
= 48
Number of stickers that Kimberly had in the end = 4 p
4 p = 48
1 p = 48 ÷ 4 = 12
Number of stickers that Kimberly had after receiving some stickers from Zoe
= 5 p
= 5 x 12
= 60
Number of stickers that Zoe had after giving to Kimberly
= 96 - 60
= 36
2 u = 36
1 u = 36 ÷ 2 = 18
Number of stickers that Zoe had at first
= 3 u
= 3 x 18
= 54
Number of stickers that Kimberly had at first
= 96 - 54
= 42
Answer(s): 42