Esther and Jaslyn had a total of 140 stickers. Jaslyn gave
15 of her stickers to Esther. In return, Esther gave
18 of the total number of stickers that she had to Jaslyn. In the end, each girl had the same number of stickers. How many stickers did Esther have at first?
|
Esther |
Jaslyn |
Total |
Before 1 |
? |
5 u |
140 |
Change 1 |
+ 1 u |
- 1 u |
|
After 1 |
80 |
4 u |
140 |
Before 2 |
8 p |
4 u |
140 |
Change 2 |
- 1 p |
+ 1 p |
|
After 2 |
7 p (70) |
70 |
140 |
Since Jaslyn gave some stickers to Esther and Esther then gave some stickers to Jaslyn, it is an internal transfer of stickers between the two girls. So, the total number of stickers remains unchanged.
Number of stickers that Jaslyn and Esther each had in the end is the same.
Number of stickers that Esther had in the end
= 140 ÷ 2
= 70
Number of stickers that Esther had in the end = 7 p
7 p = 70
1 p = 70 ÷ 7 = 10
Number of stickers that Esther had after receiving some stickers from Jaslyn
= 8 p
= 8 x 10
= 80
Number of stickers that Jaslyn had after giving to Esther
= 140 - 80
= 60
4 u = 60
1 u = 60 ÷ 4 = 15
Number of stickers that Jaslyn had at first
= 5 u
= 5 x 15
= 75
Number of stickers that Esther had at first
= 140 - 75
= 65
Answer(s): 65