Peter School had 565 pupils and Ken School had 40% less pupils. When an equal number of pupils joined each school, the ratio of the pupils in Ken School to that in Peter School became 3 : 2. How many pupils were there in both schools in the end?
|
Peter School |
Ken School |
Difference |
Before |
565 |
|
226 |
Change |
+ ? |
+ ? |
|
After |
3 u |
2 u |
1 u |
Since an equal number of pupils joined each school, the difference in the number of pupils at first and in the end between the 2 schools remains the same. Make the difference between the number of pupils in Peter School and Ken School at first and in the end the same.
Difference between the number of pupils in both schools at first
= 40% x 565
=
40100 x 565
= 226
Difference between the number of pupils in both schools in the end
= 3 u - 2 u
= 1 u
1 u = 226
Total number of pupils in both schools in the end
= 3 u + 2 u
= 5 u
= 5 x 226
= 1130
Answer(s): 1130