Opal baked 168 croissants. ⁵₈ of the croissants were mocha croissants. The rest were chocolate croissants. She gave an equal number of mocha croissants and chocolate croissants away and had 4 times as many mocha croissants as chocolate croissants left. How many croissants did she give away?

	Mocha croissants	Chocolate croissants	Difference
Before	5x3 = 15 u	3x3 = 9 u	2x3 = 6 u
Change	- 7 u	- 7 u
After	4x2 = 8 u	1x2 = 2 u	3x2 = 6 u

Since Opal gave away an equal number of mocha croissants and chocolate croissants, the difference in the number of mocha croissants and chocolate croissants remains unchanged.  Make the difference in the mocha croissants and chocolate croissants the same.  LCM of 2 and 3 is 6.

Total number of croissants at first
= 15 u + 9 u
= 24 u

24 u = 168

1 u = 168 ÷ 24 = 7

Number of croissants that Opal gave away
= 7 u + 7 u
= 14 u
= 14 x 7 
= 98

Answer(s): 98