Valen and Jenson had 58 beads in total. Jenson had 6 beads more than Valen at first. After Valen and Jenson played a game with Hazel, Valen had
14 as many beads as Jenson. If Valen lost as many beads as Jenson to Hazel, find the number of beads that Valen lost to Hazel.
|
Valen |
Jenson |
Difference |
Before |
1 u |
1 u + 6 |
6 |
Change |
- ? |
- ? |
|
After |
1 p |
4 p |
3 p |
Total number of beads at first
= 1 u + 1 u + 6
= 2 u + 6
2 u + 6 = 58
2 u = 58 - 6
2 u = 52
1 u = 52 ÷ 2 = 26
Since Valen lost the same number of beads as Jenson, the difference in the number of beads between Valen and Jenson at first and in the end remains the same.
Difference in the number of beads in the end
= 4 p - 1 p
= 3 p
3 p = 6
1 p = 6 ÷ 3 = 2
Number of beads that Valen lost to Hazel
= 1 u - 1 p
= 26 - 1 x 2
= 26 - 2
= 24
Answer(s): 24