Eric and Jack had 104 marbles in total. Eric had 54 marbles less than Jack at first. After Eric and Jack played a game with Winnie, Eric had
17 as many marbles as Jack. If Eric lost as many marbles as Jack to Winnie, find the number of marbles that Jack lost to Winnie.
|
Eric |
Jack |
Difference |
Before |
1 u |
1 u + 54 |
54 |
Change |
- ? |
- ? |
|
After |
1 p |
7 p |
6 p |
Total number of marbles at first
= 1 u + 1 u + 54
= 2 u + 54
2 u + 54 = 104
2 u = 104 - 54
2 u = 50
1 u = 50 ÷ 2 = 25
Since Eric lost the same number of marbles as Jack, the difference in the number of marbles between Eric and Jack at first and in the end remains the same.
Difference in the number of marbles in the end
= 7 p - 1 p
= 6 p
6 p = 54
1 p = 54 ÷ 6 = 9
Number of marbles that Eric lost to Winnie
= 1 u - 1 p
= 25 - 1 x 9
= 25 - 9
= 16
Since Jack lost the same number of marbles as Eric, the number of marbles that each lost to Winnie is the same.
Number of marbles that Jack lost = 16
Answer(s): 16