Paul and Rael had 69 marbles in total. Paul had 25 marbles less than Rael at first. After Paul and Rael played a game with Jade, Paul had
16 as many marbles as Rael. If Paul lost as many marbles as Rael to Jade, find the number of marbles that Rael lost to Jade.
|
Paul |
Rael |
Difference |
Before |
1 u |
1 u + 25 |
25 |
Change |
- ? |
- ? |
|
After |
1 p |
6 p |
5 p |
Total number of marbles at first
= 1 u + 1 u + 25
= 2 u + 25
2 u + 25 = 69
2 u = 69 - 25
2 u = 44
1 u = 44 ÷ 2 = 22
Since Paul lost the same number of marbles as Rael, the difference in the number of marbles between Paul and Rael at first and in the end remains the same.
Difference in the number of marbles in the end
= 6 p - 1 p
= 5 p
5 p = 25
1 p = 25 ÷ 5 = 5
Number of marbles that Paul lost to Jade
= 1 u - 1 p
= 22 - 1 x 5
= 22 - 5
= 17
Since Rael lost the same number of marbles as Paul, the number of marbles that each lost to Jade is the same.
Number of marbles that Rael lost = 17
Answer(s): 17