Warren and Lee had 100 beads in total. Warren had 36 beads less than Lee at first. After Warren and Lee played a game with Linda, Warren had ¹₅ as many beads as Lee. If Warren lost as many beads as Lee to Linda, find the number of beads that Lee lost to Linda.

	Warren	Lee	Difference
Before	1 u	1 u + 36	36
Change	- ?	- ?
After	1 p	5 p	4 p

Total number of beads at first
= 1 u + 1 u + 36 
= 2 u + 36

2 u + 36 = 100
2 u = 100 - 36
2 u = 64

1 u = 64 ÷ 2 = 32

Since Warren lost the same number of beads as Lee, the difference in the number of beads between Warren and Lee at first and in the end remains the same.

Difference in the number of beads in the end
= 5 p - 1 p
= 4 p

4 p = 36

1 p = 36 ÷ 4 = 9

Number of beads that Warren lost to Linda
= 1 u - 1 p
= 32 - 1 x 9
= 32 - 9
= 23

Since Lee lost the same number of beads as Warren, the number of beads that each lost to Linda is the same.

Number of beads that Lee lost = 23

Answer(s): 23