Howard and Albert had 72 stickers in total. Howard had 8 stickers less than Albert at first. After Howard and Albert played a game with Tina, Howard had
57 as many stickers as Albert. If Howard lost as many stickers as Albert to Tina, find the number of stickers that Albert lost to Tina.
|
Howard |
Albert |
Difference |
Before |
1 u |
1 u + 8 |
8 |
Change |
- ? |
- ? |
|
After |
5 p |
7 p |
2 p |
Total number of stickers at first
= 1 u + 1 u + 8
= 2 u + 8
2 u + 8 = 72
2 u = 72 - 8
2 u = 64
1 u = 64 ÷ 2 = 32
Since Howard lost the same number of stickers as Albert, the difference in the number of stickers between Howard and Albert at first and in the end remains the same.
Difference in the number of stickers in the end
= 7 p - 5 p
= 2 p
2 p = 8
1 p = 8 ÷ 2 = 4
Number of stickers that Howard lost to Tina
= 1 u - 5 p
= 32 - 5 x 4
= 32 - 20
= 12
Since Albert lost the same number of stickers as Howard, the number of stickers that each lost to Tina is the same.
Number of stickers that Albert lost = 12
Answer(s): 12