Andy and Reggie had 64 beads in total. Andy had 6 beads less than Reggie at first. After Andy and Reggie played a game with Zoe, Andy had
79 as many beads as Reggie. If Andy lost as many beads as Reggie to Zoe, find the number of beads that Reggie lost to Zoe.
|
Andy |
Reggie |
Difference |
Before |
1 u |
1 u + 6 |
6 |
Change |
- ? |
- ? |
|
After |
7 p |
9 p |
2 p |
Total number of beads at first
= 1 u + 1 u + 6
= 2 u + 6
2 u + 6 = 64
2 u = 64 - 6
2 u = 58
1 u = 58 ÷ 2 = 29
Since Andy lost the same number of beads as Reggie, the difference in the number of beads between Andy and Reggie at first and in the end remains the same.
Difference in the number of beads in the end
= 9 p - 7 p
= 2 p
2 p = 6
1 p = 6 ÷ 2 = 3
Number of beads that Andy lost to Zoe
= 1 u - 7 p
= 29 - 7 x 3
= 29 - 21
= 8
Since Reggie lost the same number of beads as Andy, the number of beads that each lost to Zoe is the same.
Number of beads that Reggie lost = 8
Answer(s): 8