Bobby and Neave had 66 beads in total. Bobby had 10 beads less than Neave at first. After Bobby and Neave played a game with Usha, Bobby had
611 as many beads as Neave. If Bobby lost as many beads as Neave to Usha, find the number of beads that Neave lost to Usha.
|
Bobby |
Neave |
Difference |
Before |
1 u |
1 u + 10 |
10 |
Change |
- ? |
- ? |
|
After |
6 p |
11 p |
5 p |
Total number of beads at first
= 1 u + 1 u + 10
= 2 u + 10
2 u + 10 = 66
2 u = 66 - 10
2 u = 56
1 u = 56 ÷ 2 = 28
Since Bobby lost the same number of beads as Neave, the difference in the number of beads between Bobby and Neave at first and in the end remains the same.
Difference in the number of beads in the end
= 11 p - 6 p
= 5 p
5 p = 10
1 p = 10 ÷ 5 = 2
Number of beads that Bobby lost to Usha
= 1 u - 6 p
= 28 - 6 x 2
= 28 - 12
= 16
Since Neave lost the same number of beads as Bobby, the number of beads that each lost to Usha is the same.
Number of beads that Neave lost = 16
Answer(s): 16