Will and Lee had 178 marbles in total. Will had 132 marbles less than Lee at first. After Will and Lee played a game with Gem, Will had ¹₁₂ as many marbles as Lee. If Will lost as many marbles as Lee to Gem, find the number of marbles that Lee lost to Gem.

	Will	Lee	Difference
Before	1 u	1 u + 132	132
Change	- ?	- ?
After	1 p	12 p	11 p

Total number of marbles at first
= 1 u + 1 u + 132 
= 2 u + 132

2 u + 132 = 178
2 u = 178 - 132
2 u = 46

1 u = 46 ÷ 2 = 23

Since Will lost the same number of marbles as Lee, the difference in the number of marbles between Will and Lee at first and in the end remains the same.

Difference in the number of marbles in the end
= 12 p - 1 p
= 11 p

11 p = 132

1 p = 132 ÷ 11 = 12

Number of marbles that Will lost to Gem
= 1 u - 1 p
= 23 - 1 x 12
= 23 - 12
= 11

Since Lee lost the same number of marbles as Will, the number of marbles that each lost to Gem is the same.

Number of marbles that Lee lost = 11

Answer(s): 11