Zane and Pierre had 81 marbles in total. Zane had 33 marbles less than Pierre at first. After Zane and Pierre played a game with Jean, Zane had
25 as many marbles as Pierre. If Zane lost as many marbles as Pierre to Jean, find the number of marbles that Pierre lost to Jean.
|
Zane |
Pierre |
Difference |
Before |
1 u |
1 u + 33 |
33 |
Change |
- ? |
- ? |
|
After |
2 p |
5 p |
3 p |
Total number of marbles at first
= 1 u + 1 u + 33
= 2 u + 33
2 u + 33 = 81
2 u = 81 - 33
2 u = 48
1 u = 48 ÷ 2 = 24
Since Zane lost the same number of marbles as Pierre, the difference in the number of marbles between Zane and Pierre at first and in the end remains the same.
Difference in the number of marbles in the end
= 5 p - 2 p
= 3 p
3 p = 33
1 p = 33 ÷ 3 = 11
Number of marbles that Zane lost to Jean
= 1 u - 2 p
= 24 - 2 x 11
= 24 - 22
= 2
Since Pierre lost the same number of marbles as Zane, the number of marbles that each lost to Jean is the same.
Number of marbles that Pierre lost = 2
Answer(s): 2