Pierre and Asher had 32 beads in total. Pierre had 6 beads less than Asher at first. After Pierre and Asher played a game with Yoko, Pierre had
14 as many beads as Asher. If Pierre lost as many beads as Asher to Yoko, find the number of beads that Asher lost to Yoko.
|
Pierre |
Asher |
Difference |
Before |
1 u |
1 u + 6 |
6 |
Change |
- ? |
- ? |
|
After |
1 p |
4 p |
3 p |
Total number of beads at first
= 1 u + 1 u + 6
= 2 u + 6
2 u + 6 = 32
2 u = 32 - 6
2 u = 26
1 u = 26 ÷ 2 = 13
Since Pierre lost the same number of beads as Asher, the difference in the number of beads between Pierre and Asher at first and in the end remains the same.
Difference in the number of beads in the end
= 4 p - 1 p
= 3 p
3 p = 6
1 p = 6 ÷ 3 = 2
Number of beads that Pierre lost to Yoko
= 1 u - 1 p
= 13 - 1 x 2
= 13 - 2
= 11
Since Asher lost the same number of beads as Pierre, the number of beads that each lost to Yoko is the same.
Number of beads that Asher lost = 11
Answer(s): 11