A fruit seller had pears and persimmons. The ratio of pears to persimmons was 3 : 8. After
12 of the pears and 40 persimmons were sold, there were 2 times as many pears as persimmons left. How many pears and persimmons were there at first?
| |
Pears |
Persimmons |
Total |
| Before |
3 u |
8 u |
11 u |
| Change |
- 1.5 u |
- 40 |
|
| After |
1.5 u |
3 u |
|
Number of pears sold
=
12 x 3 u
= 1.5 u
Number of pears left
= 3 u - 1.5 u
= 1.5 u
Number of persimmons left
= 2 x 1.5 u
= 3 u
Number of persimmons sold
= 8 u - 3 u
= 5 u
5 u = 40
1 u = 40 ÷ 5 = 8
Number of pears and persimmons at first
= 3 u + 8 u
= 11 u
= 11 x 8
= 88
Answer(s): 88
