A fruit seller had persimmons and chikoos. The ratio of persimmons to chikoos was 3 : 10. After
12 of the persimmons and 44 chikoos were sold, there were 3 times as many persimmons as chikoos left. How many persimmons and chikoos were there at first?
| |
Persimmons |
Chikoos |
Total |
| Before |
3 u |
10 u |
13 u |
| Change |
- 1.5 u |
- 44 |
|
| After |
1.5 u |
4.5 u |
|
Number of persimmons sold
=
12 x 3 u
= 1.5 u
Number of persimmons left
= 3 u - 1.5 u
= 1.5 u
Number of chikoos left
= 3 x 1.5 u
= 4.5 u
Number of chikoos sold
= 10 u - 4.5 u
= 5.5 u
5.5 u = 44
1 u = 44 ÷ 5.5 = 8
Number of persimmons and chikoos at first
= 3 u + 10 u
= 13 u
= 13 x 8
= 104
Answer(s): 104
