A fruit seller had pears and persimmons. The ratio of pears to persimmons was 3 : 10. After
12 of the pears and 99 persimmons were sold, there were 3 times as many pears as persimmons left. How many pears and persimmons were there at first?
|
Pears |
Persimmons |
Total |
Before |
3 u |
10 u |
13 u |
Change |
- 1.5 u |
- 99 |
|
After |
1.5 u |
4.5 u |
|
Number of pears sold
=
12 x 3 u
= 1.5 u
Number of pears left
= 3 u - 1.5 u
= 1.5 u
Number of persimmons left
= 3 x 1.5 u
= 4.5 u
Number of persimmons sold
= 10 u - 4.5 u
= 5.5 u
5.5 u = 99
1 u = 99 ÷ 5.5 = 18
Number of pears and persimmons at first
= 3 u + 10 u
= 13 u
= 13 x 18
= 234
Answer(s): 234