A fruit seller had apples and persimmons. The ratio of apples to persimmons was 2 : 7. After
14 of the apples and 20 persimmons were sold, there were 3 times as many apples as persimmons left. How many apples and persimmons were there at first?
| |
Apples |
Persimmons |
Total |
| Before |
2 u |
7 u |
9 u |
| Change |
- 0.5 u |
- 20 |
|
| After |
1.5 u |
4.5 u |
|
Number of apples sold
=
14 x 2 u
= 0.5 u
Number of apples left
= 2 u - 0.5 u
= 1.5 u
Number of persimmons left
= 3 x 1.5 u
= 4.5 u
Number of persimmons sold
= 7 u - 4.5 u
= 2.5 u
2.5 u = 20
1 u = 20 ÷ 2.5 = 8
Number of apples and persimmons at first
= 2 u + 7 u
= 9 u
= 9 x 8
= 72
Answer(s): 72
