At a fruit stall, there were 255 pears and apples at first.
25 of the pears and
17 of the apples were sold. In the end, there were same number of pears and apples. How many more pears than apples were sold?
| |
Pears |
Apples |
| Before |
5x2 =
10 u |
7x1 =
7 u |
| Change |
- 2x2 =
- 4 u
|
- 1x1 =
- 1 u
|
| After |
3x2 =
6 u |
6x1 =
6 u |
Comparing pears
and apples in the end |
1x6 =
6 u |
1x6 =
6 u |
The number of pears and apples in the end is the same. Make the number of pears and apples in the end the same. LCM of 3, 6 and 1 is 6.
Number of pears and apples in the end
= 10 u + 7 u
= 17 u
17 u = 255
1 u = 255 ÷ 17 = 15
Number of more pears than apples sold
= 4 u - 1 u
= 3 u
= 3 x 15
= 45
Answer(s): 45
