At a fruit stall, there were 333 kiwis and pears at first.
35 of the kiwis and
16 of the pears were sold. In the end, there were same number of kiwis and pears. How many more kiwis than pears were sold?
| |
Kiwis |
Pears |
| Before |
5x5 =
25 u |
6x2 =
12 u |
| Change |
- 3x5 =
- 15 u
|
- 1x2 =
- 2 u
|
| After |
2x5 =
10 u |
5x2 =
10 u |
Comparing kiwis
and pears in the end |
1x10 =
10 u |
1x10 =
10 u |
The number of kiwis and pears in the end is the same. Make the number of kiwis and pears in the end the same. LCM of 2, 5 and 1 is 10.
Number of kiwis and pears in the end
= 25 u + 12 u
= 37 u
37 u = 333
1 u = 333 ÷ 37 = 9
Number of more kiwis than pears sold
= 15 u - 2 u
= 13 u
= 13 x 9
= 117
Answer(s): 117
