At a fruit stall, there were 1040 oranges and chikoos at first.
14 of the oranges and
18 of the chikoos were sold. In the end, there were same number of oranges and chikoos. How many more oranges than chikoos were sold?
| |
Oranges |
Chikoos |
| Before |
4x7 =
28 u |
8x3 =
24 u |
| Change |
- 1x7 =
- 7 u
|
- 1x3 =
- 3 u
|
| After |
3x7 =
21 u |
7x3 =
21 u |
Comparing oranges
and chikoos in the end |
1x21 =
21 u |
1x21 =
21 u |
The number of oranges and chikoos in the end is the same. Make the number of oranges and chikoos in the end the same. LCM of 3, 7 and 1 is 21.
Number of oranges and chikoos in the end
= 28 u + 24 u
= 52 u
52 u = 1040
1 u = 1040 ÷ 52 = 20
Number of more oranges than chikoos sold
= 7 u - 3 u
= 4 u
= 4 x 20
= 80
Answer(s): 80
