At a fruit stall, there were 969 chikoos and pears at first.
35 of the chikoos and
18 of the pears were sold. In the end, there were same number of chikoos and pears. How many more chikoos than pears were sold?
|
Chikoos |
Pears |
Before |
5x7 = 35 u |
8x2 = 16 u |
Change |
- 3x7 = - 21 u
|
- 1x2 = - 2 u
|
After |
2x7 = 14 u |
7x2 = 14 u |
Comparing chikoos and pears in the end |
1x14 = 14 u |
1x14 = 14 u |
The number of chikoos and pears in the end is the same. Make the number of chikoos and pears in the end the same. LCM of 2, 7 and 1 is 14.
Number of chikoos and pears in the end
= 35 u + 16 u
= 51 u
51 u = 969
1 u = 969 ÷ 51 = 19
Number of more chikoos than pears sold
= 21 u - 2 u
= 19 u
= 19 x 19
= 361
Answer(s): 361