At a fruit stall, there were 220 kiwis and persimmons at first.
35 of the kiwis and
17 of the persimmons were sold. In the end, there were same number of kiwis and persimmons. How many more kiwis than persimmons were sold?
| |
Kiwis |
Persimmons |
| Before |
5x3 =
15 u |
7x1 =
7 u |
| Change |
- 3x3 =
- 9 u
|
- 1x1 =
- 1 u
|
| After |
2x3 =
6 u |
6x1 =
6 u |
Comparing kiwis
and persimmons in the end |
1x6 =
6 u |
1x6 =
6 u |
The number of kiwis and persimmons in the end is the same. Make the number of kiwis and persimmons in the end the same. LCM of 2, 6 and 1 is 6.
Number of kiwis and persimmons in the end
= 15 u + 7 u
= 22 u
22 u = 220
1 u = 220 ÷ 22 = 10
Number of more kiwis than persimmons sold
= 9 u - 1 u
= 8 u
= 8 x 10
= 80
Answer(s): 80
