At a fruit stall, there were 102 chikoos and apples at first.
25 of the chikoos and
17 of the apples were sold. In the end, there were same number of chikoos and apples. How many more chikoos than apples were sold?
| |
Chikoos |
Apples |
| Before |
5x2 =
10 u |
7x1 =
7 u |
| Change |
- 2x2 =
- 4 u
|
- 1x1 =
- 1 u
|
| After |
3x2 =
6 u |
6x1 =
6 u |
Comparing chikoos
and apples in the end |
1x6 =
6 u |
1x6 =
6 u |
The number of chikoos and apples in the end is the same. Make the number of chikoos and apples in the end the same. LCM of 3, 6 and 1 is 6.
Number of chikoos and apples in the end
= 10 u + 7 u
= 17 u
17 u = 102
1 u = 102 ÷ 17 = 6
Number of more chikoos than apples sold
= 4 u - 1 u
= 3 u
= 3 x 6
= 18
Answer(s): 18
