At a fruit stall, there were 860 kiwis and pears at first.
25 of the kiwis and
16 of the pears were sold. In the end, there were same number of kiwis and pears. How many less pears than kiwis were sold?
| |
Kiwis |
Pears |
| Before |
5x5 =
25 u |
6x3 =
18 u |
| Change |
- 2x5 =
- 10 u
|
- 1x3 =
- 3 u
|
| After |
3x5 =
15 u |
5x3 =
15 u |
Comparing kiwis
and pears in the end |
1x15 =
15 u |
1x15 =
15 u |
The number of kiwis and pears in the end is the same. Make the number of kiwis and pears in the end the same. LCM of 3, 5 and 1 is 15.
Number of kiwis and pears in the end
= 25 u + 18 u
= 43 u
43 u = 860
1 u = 860 ÷ 43 = 20
Number of less pears than kiwis were sold
= 10 u - 3 u
= 7 u
= 7 x 20
= 140
Answer(s): 140
