At a fruit stall, there were 215 pears and persimmons at first.
25 of the pears and
16 of the persimmons were sold. In the end, there were same number of pears and persimmons. How many less persimmons than pears were sold?
| |
Pears |
Persimmons |
| Before |
5x5 =
25 u |
6x3 =
18 u |
| Change |
- 2x5 =
- 10 u
|
- 1x3 =
- 3 u
|
| After |
3x5 =
15 u |
5x3 =
15 u |
Comparing pears
and persimmons in the end |
1x15 =
15 u |
1x15 =
15 u |
The number of pears and persimmons in the end is the same. Make the number of pears and persimmons in the end the same. LCM of 3, 5 and 1 is 15.
Number of pears and persimmons in the end
= 25 u + 18 u
= 43 u
43 u = 215
1 u = 215 ÷ 43 = 5
Number of less persimmons than pears were sold
= 10 u - 3 u
= 7 u
= 7 x 5
= 35
Answer(s): 35
