At a fruit stall, there were 119 oranges and pears at first.
25 of the oranges and
17 of the pears were sold. In the end, there were same number of oranges and pears. How many more oranges than pears were sold?
| |
Oranges |
Pears |
| Before |
5x2 =
10 u |
7x1 =
7 u |
| Change |
- 2x2 =
- 4 u
|
- 1x1 =
- 1 u
|
| After |
3x2 =
6 u |
6x1 =
6 u |
Comparing oranges
and pears in the end |
1x6 =
6 u |
1x6 =
6 u |
The number of oranges and pears in the end is the same. Make the number of oranges and pears in the end the same. LCM of 3, 6 and 1 is 6.
Number of oranges and pears in the end
= 10 u + 7 u
= 17 u
17 u = 119
1 u = 119 ÷ 17 = 7
Number of more oranges than pears sold
= 4 u - 1 u
= 3 u
= 3 x 7
= 21
Answer(s): 21
