At a fruit stall, there were 340 chikoos and pears at first.
35 of the chikoos and
37 of the pears were sold. In the end, there were same number of chikoos and pears. How many less pears than chikoos were sold?
| |
Chikoos |
Pears |
| Before |
5x2 =
10 u |
7x1 =
7 u |
| Change |
- 3x2 =
- 6 u
|
- 3x1 =
- 3 u
|
| After |
2x2 =
4 u |
4x1 =
4 u |
Comparing chikoos
and pears in the end |
1x4 =
4 u |
1x4 =
4 u |
The number of chikoos and pears in the end is the same. Make the number of chikoos and pears in the end the same. LCM of 2, 4 and 1 is 4.
Number of chikoos and pears in the end
= 10 u + 7 u
= 17 u
17 u = 340
1 u = 340 ÷ 17 = 20
Number of less pears than chikoos were sold
= 6 u - 3 u
= 3 u
= 3 x 20
= 60
Answer(s): 60
