Xylia made 275 biscuits and croissants. After she gave 0.7 of the biscuits and 0.8 of the croissants to her girls, she was left with an equal number of biscuits and croissants. How many biscuits had she left?
| |
Biscuits |
Croissants |
Before
|
10x1 =
10 u |
5x3 =
15 u |
Change
|
- 7x1 =
- 7 u |
- 4x3 =
- 12 u |
After
|
3x1 =
3 u |
1x3 =
3 u |
Comparing biscuits and
croissants in the end |
1x3 =
3 u |
1x3 =
3 u |
0.7 =
710 0.8 =
810 =
45 The number of biscuits and croissants is the same in the end. Make the number of biscuits and croissants in the end the same. LCM of 3 and 1 and 1 is 3.
Total number of biscuits and croissants at first
= 10 u + 15 u
= 25 u
25 u = 275
1 u = 275 ÷ 25 = 11
Number of biscuits that Xylia had left
= 3 u
= 3 x 11
= 33
Answer(s): 33
