Charlie had pears and oranges. The ratio of pears to oranges was 7 : 3. After
34 of the pears and 77 oranges were sold, there were 7 times as many pears as oranges left. How many pears and oranges were sold?
| |
Pears |
Oranges |
Comparing pears
and oranges at first |
7x4 =
28 u |
3x4 =
12 u |
| Before |
4x7 =
28 u |
|
| Change |
- 3x7 =
- 21 u |
- 77 |
| After |
1x7 =
7 u |
|
Comparing pears
and oranges in the end |
7 u |
1 u |
The number of pears at first is repeated. Make the number of pears at first the same. LCM of 7 and 4 is 28.
Number of oranges sold
= 12 u - 1 u
= 11 u
11 u = 77
1 u = 77 ÷ 11 = 7
Number of pears and oranges sold
= 21 u + 77
= 21 x 7 + 77
= 147 + 77
= 224
Answer(s): 224
