Seth had chikoos and oranges. The ratio of chikoos to oranges was 8 : 5. After
12 of the chikoos and 24 oranges were sold, there were 4 times as many chikoos as oranges left. How many chikoos and oranges were there at first?
| |
Chikoos |
Oranges |
Comparing chikoos
and oranges at first |
8x1 =
8 u |
5x1 =
5 u |
| Before |
2x4 =
8 u |
|
| Change |
- 1x4 =
- 4 u |
- 24 |
| After |
1x4 =
4 u |
|
Comparing chikoos
and oranges in the end |
4 u |
1 u |
The number of chikoos at first is repeated. Make the number of chikoos at first the same. LCM of 8 and 2 is 8.
Number of oranges sold
= 5 u - 1 u
= 4 u
4 u = 24
1 u = 24 ÷ 4 = 6
Number of chikoos and oranges at first
= 8 u + 5 u
= 13 u
= 13 x 6
= 78
Answer(s): 78
