Simon had chikoos and pears. The ratio of chikoos to pears was 8 : 5. After
14 of the chikoos and 36 pears were sold, there were 6 times as many chikoos as pears left. How many chikoos and pears were there at first?
| |
Chikoos |
Pears |
Comparing chikoos
and pears at first |
8x1 =
8 u |
5x1 =
5 u |
| Before |
4x2 =
8 u |
|
| Change |
- 1x2 =
- 2 u |
- 36 |
| After |
3x2 =
6 u |
|
Comparing chikoos
and pears in the end |
6 u |
1 u |
The number of chikoos at first is repeated. Make the number of chikoos at first the same. LCM of 8 and 4 is 8.
Number of pears sold
= 5 u - 1 u
= 4 u
4 u = 36
1 u = 36 ÷ 4 = 9
Number of chikoos and pears at first
= 8 u + 5 u
= 13 u
= 13 x 9
= 117
Answer(s): 117
