Carl had a total of 350 notes. The notes are $2 notes and $10 notes. After he spent 90% of the $2 notes and 60% of the $10 notes on one stand mixer, he was left with 3 times as many $10 notes as $2 notes. How much did the stand mixer cost?
|
$2 |
$10 |
Before |
10x2 = 20 u |
5x3 = 15 u
|
Change |
- 9x2 = - 18 u |
- 3x3 = - 9 u
|
After |
1x2 = 2 u |
2x3 = 6 u |
Comparing $2 and $10 in the end |
1x2 = 2 u
|
3x2 = 6 u |
90% of $2 notes =
90
100 of $2 notes =
910 of $2 notes
60% of $10 notes =
60100 of $10 notes =
35 of $10 notes
The number of $2 notes in the end is repeated. Make the number of $2 notes the same. LCM of 2 and 3 is 6.
The number of $10 notes in the end is repeated. Make the number of $10 notes the same. LCM of 1 and 2 is 2.
Number of notes at first
= 20 u + 15 u
= 35 u
35 u = 350
1 u = 350 ÷ 35 = 10
|
$2 |
$10 |
Number |
18 u |
9 u |
Value |
2 |
10 |
Total value |
36 u |
90 u |
Value of $2 spent
= 18 u x 2
= 36 u
Value of $10 spent
= 9 u x 10
= 90 u
Price of the stand mixer
= 36 u + 90 u
= 126 u
= 126 x 10
= $1260
Answer(s): $1260