Carl had a total of 112 notes. The notes are $2 notes and $10 notes. After he spent 75% of the $2 notes and 60% of the $10 notes on one refrigerator, he was left with 4 times as many $10 notes as $2 notes. How much did the refrigerator cost?
|
$2 |
$10 |
Before |
4x1 = 4 u |
5x2 = 10 u
|
Change |
- 3x1 = - 3 u |
- 3x2 = - 6 u
|
After |
1x1 = 1 u |
2x2 = 4 u |
Comparing $2 and $10 in the end |
1x1 = 1 u
|
4x1 = 4 u |
75% of $2 notes =
75
100 of $2 notes =
34 of $2 notes
60% of $10 notes =
60100 of $10 notes =
35 of $10 notes
The number of $2 notes in the end is repeated. Make the number of $2 notes the same. LCM of 2 and 4 is 4.
The number of $10 notes in the end is repeated. Make the number of $10 notes the same. LCM of 1 and 1 is 1.
Number of notes at first
= 4 u + 10 u
= 14 u
14 u = 112
1 u = 112 ÷ 14 = 8
|
$2 |
$10 |
Number |
3 u |
6 u |
Value |
2 |
10 |
Total value |
6 u |
60 u |
Value of $2 spent
= 3 u x 2
= 6 u
Value of $10 spent
= 6 u x 10
= 60 u
Price of the refrigerator
= 6 u + 60 u
= 66 u
= 66 x 8
= $528
Answer(s): $528