Carl had a total of 63 notes. The notes are $2 notes and $10 notes. After he spent 80% of the $2 notes and 75% of the $10 notes on one stand mixer, he was left with 4 times as many $10 notes as $2 notes. How much did the stand mixer cost?
|
$2 |
$10 |
Before |
5x1 = 5 u |
4x4 = 16 u
|
Change |
- 4x1 = - 4 u |
- 3x4 = - 12 u
|
After |
1x1 = 1 u |
1x4 = 4 u |
Comparing $2 and $10 in the end |
1x1 = 1 u
|
4x1 = 4 u |
80% of $2 notes =
80
100 of $2 notes =
45 of $2 notes
75% of $10 notes =
75100 of $10 notes =
34 of $10 notes
The number of $2 notes in the end is repeated. Make the number of $2 notes the same. LCM of 1 and 4 is 4.
The number of $10 notes in the end is repeated. Make the number of $10 notes the same. LCM of 1 and 1 is 1.
Number of notes at first
= 5 u + 16 u
= 21 u
21 u = 63
1 u = 63 ÷ 21 = 3
|
$2 |
$10 |
Number |
4 u |
12 u |
Value |
2 |
10 |
Total value |
8 u |
120 u |
Value of $2 spent
= 4 u x 2
= 8 u
Value of $10 spent
= 12 u x 10
= 120 u
Price of the stand mixer
= 8 u + 120 u
= 128 u
= 128 x 3
= $384
Answer(s): $384