Carl had a total of 69 notes. The notes are $5 notes and $10 notes. After he spent 75% of the $5 notes and 60% of the $10 notes on one stand mixer, he was left with 3 times as many $10 notes as $5 notes. How much did the stand mixer cost?
|
$5 |
$10 |
Before |
4x2 = 8 u |
5x3 = 15 u
|
Change |
- 3x2 = - 6 u |
- 3x3 = - 9 u
|
After |
1x2 = 2 u |
2x3 = 6 u |
Comparing $5 and $10 in the end |
1x2 = 2 u
|
3x2 = 6 u |
75% of $5 notes =
75
100 of $5 notes =
34 of $5 notes
60% of $10 notes =
60100 of $10 notes =
35 of $10 notes
The number of $5 notes in the end is repeated. Make the number of $5 notes the same. LCM of 2 and 3 is 6.
The number of $10 notes in the end is repeated. Make the number of $10 notes the same. LCM of 1 and 2 is 2.
Number of notes at first
= 8 u + 15 u
= 23 u
23 u = 69
1 u = 69 ÷ 23 = 3
|
$5 |
$10 |
Number |
6 u |
9 u |
Value |
5 |
10 |
Total value |
30 u |
90 u |
Value of $5 spent
= 6 u x 5
= 30 u
Value of $10 spent
= 9 u x 10
= 90 u
Price of the stand mixer
= 30 u + 90 u
= 120 u
= 120 x 3
= $360
Answer(s): $360