Gillian had $70 less than Marion. Marion spent 0.6 of her money and Gillian spent 40% of her money. In the end, Marion and Gillian had the same amount of money left. Find the amount of money that Marion had at first.
| |
Gillian |
Marion |
Comparing Marion
and Gillian at first |
|
70 more |
| Before |
5x2 =
10 u |
5x3 =
15 u |
| Change |
- 2x2 =
- 4 u |
- 3x3 =
- 9 u |
| After |
3x2 =
6 u |
2x3 =
6 u |
0.6 =
610 =
35 40% =
40100 =
25 Gillian and Marion had the same amount of money in the end. Make the amount that each had in the end the same. LCM of 2 and 3 is 6.
Amount that Gillian had less than Marion at first
= 15 u - 10 u
= 5 u
5 u = 70
1 u = 70 ÷ 5 = 14
Amount that Marion had at first
= 15 u
= 15 x 14
= $210
Answer(s): $210
