Opal had some coin collection.
18 of them were gold and the rest were silver. She gave away 148 of the silver coins and 50% of the gold coins. She then had
16 of her coin collection left. How many coins did Opal give away?
| |
Gold |
Silver |
Total |
Total |
Before
|
1x3 =
3 u |
7x3 =
21 u |
8x3 =
24 u |
6x4 =
24 u |
Change
|
- 0.5x3 =
- 1.5 u |
- 148 |
|
- 5x4 =
- 20 u |
After
|
0.5x3 =
1.5 u |
21 u - 148 |
|
1x4 =
4 u |
The total number of coins that Opal had at first is repeated. Make the total number of coins at first the same. LCM 8 and 6 is 24.
Number of gold coins that Opal gave away
= 50% x 1 u
=
50100 x 1 u
= 0.5 u
1.5 u - 148 = 20 u
20 u - 1.5 u = 148
18.5 u = 148
1 u = 148 ÷ 18.5 = 8
Number of coins that Opal gave away
= 20 u
= 20 x 8
= 160
Answer(s): 160
