Marion had some coin collection.
13 of them were yellow and the rest were green. She gave away 120 of the green coins and 10% of the yellow coins. She then had
16 of her coin collection left. How many coins did Marion give away?
| |
Yellow |
Green |
Total |
Total |
Before
|
1x2 =
2 u |
2x2 =
4 u |
3x2 =
6 u |
6x1 =
6 u |
Change
|
- 0.1x2 =
- 0.2 u |
- 120 |
|
- 5x1 =
- 5 u |
After
|
0.9x2 =
1.8 u |
4 u - 120 |
|
1x1 =
1 u |
The total number of coins that Marion had at first is repeated. Make the total number of coins at first the same. LCM 3 and 6 is 6.
Number of yellow coins that Marion gave away
= 10% x 1 u
=
10100 x 1 u
= 0.1 u
0.2 u - 120 = 5 u
5 u - 0.2 u = 120
4.8 u = 120
1 u = 120 ÷ 4.8 = 25
Number of coins that Marion gave away
= 5 u
= 5 x 25
= 125
Answer(s): 125
