Hilda had some bead collection.
12 of them were red and the rest were purple. She gave away 140 of the purple beads and 50% of the red beads. She then had
13 of her bead collection left. How many beads did Hilda give away?
| |
Red |
Purple |
Total |
Total |
Before
|
1x3 =
3 u |
1x3 =
3 u |
2x3 =
6 u |
3x2 =
6 u |
Change
|
- 0.5x3 =
- 1.5 u |
- 140 |
|
- 2x2 =
- 4 u |
After
|
0.5x3 =
1.5 u |
3 u - 140 |
|
1x2 =
2 u |
The total number of beads that Hilda had at first is repeated. Make the total number of beads at first the same. LCM 2 and 3 is 6.
Number of red beads that Hilda gave away
= 50% x 1 u
=
50100 x 1 u
= 0.5 u
1.5 u - 140 = 4 u
4 u - 1.5 u = 140
2.5 u = 140
1 u = 140 ÷ 2.5 = 56
Number of beads that Hilda gave away
= 4 u
= 4 x 56
= 224
Answer(s): 224
