Irene had $624 less than Marion. Marion spent
47 of her money and Irene spent
34 of her money. In the end, Marion had 4 times as much as Irene. Find the amount of money Marion had at first.
| |
Marion |
Irene |
Comparing Marion
and Irene at first |
$624 more |
|
| Before |
7x4 =
28 u |
4x3 =
12 u |
| Change |
- 4x4 =
- 16 u |
- 3x3 =
- 9 u |
| After |
3x4 =
12 u |
1x3 =
3 u |
Comparing Marion
and Irene in the end |
4x3 =
12 u |
1x3 =
3 u |
The amount that Marion had in the end is repeated. Make the amount that Marion had in the end the same. LCM of 4 and 3 is 12.
Amount that Irene had less than Marion
= 28 u - 12 u
= 16 u
16 u = 624
1 u = 624 ÷ 16 = 39
Amount that Marion had at first
= 28 u
= 28 x 39
= $1092
Answer(s): $1092
