Jean had $441 less than Hilda. Hilda spent
38 of her money and Jean spent
23 of her money. In the end, Hilda had 3 times as much as Jean. Find the amount of money Hilda had at first.
| |
Hilda |
Jean |
Comparing Hilda
and Jean at first |
$441 more |
|
| Before |
8x3 =
24 u |
3x5 =
15 u |
| Change |
- 3x3 =
- 9 u |
- 2x5 =
- 10 u |
| After |
5x3 =
15 u |
1x5 =
5 u |
Comparing Hilda
and Jean in the end |
3x5 =
15 u |
1x5 =
5 u |
The amount that Hilda had in the end is repeated. Make the amount that Hilda had in the end the same. LCM of 3 and 5 is 15.
Amount that Jean had less than Hilda
= 24 u - 15 u
= 9 u
9 u = 441
1 u = 441 ÷ 9 = 49
Amount that Hilda had at first
= 24 u
= 24 x 49
= $1176
Answer(s): $1176
