Xylia had $440 less than Opal. Opal spent
47 of her money and Xylia spent
56 of her money. In the end, Opal had 4 times as much as Xylia. Find the amount of money Opal had at first.
| |
Opal |
Xylia |
Comparing Opal
and Xylia at first |
$440 more |
|
| Before |
7x4 =
28 u |
6x3 =
18 u |
| Change |
- 4x4 =
- 16 u |
- 5x3 =
- 15 u |
| After |
3x4 =
12 u |
1x3 =
3 u |
Comparing Opal
and Xylia in the end |
4x3 =
12 u |
1x3 =
3 u |
The amount that Opal had in the end is repeated. Make the amount that Opal had in the end the same. LCM of 4 and 3 is 12.
Amount that Xylia had less than Opal
= 28 u - 18 u
= 10 u
10 u = 440
1 u = 440 ÷ 10 = 44
Amount that Opal had at first
= 28 u
= 28 x 44
= $1232
Answer(s): $1232
