Risa had 168 less chocolate bars than Abi. Abi used
78 of her chocolate bars and Risa used
23 of her chocolate bars. In the end, Abi had 3 times as much as Risa. Find the number of chocolate bars that Abi had at first.
|
Abi |
Risa |
Comparing Abi and Parry at first |
|
168 less |
Before |
8x3 = 24 u |
3 u |
Change |
- 7x3 = - 21 u |
- 2 u |
After |
1x3 = 3 u |
1 u |
Comparing Abi and Parry in the end |
3 u |
1 u |
The number of chocolate bars that Abi had in the end is repeated. Make the number of chocolate bars that Abi had in the end the same. LCM of 1 and 3 is 3.
Number of chocolate bars that Risa had less than Abi
= 24 u - 3 u
= 21 u
21 u = 168
1 u = 168 ÷ 21 = 8
Number of chocolate bars that Abi had at first
= 24 u
= 24 x 8
= 192
Answer(s): 192