Gem had 80 less sweets than Hazel. Hazel used
67 of her sweets and Gem used
45 of her sweets. In the end, Hazel had 3 times as much as Gem. Find the number of sweets that Hazel had at first.
| |
Hazel |
Gem |
Comparing Hazel
and Parry at first |
|
80 less |
| Before |
7x3 =
21 u |
5 u |
| Change |
- 6x3 =
- 18 u |
- 4 u |
| After |
1x3 =
3 u |
1 u |
Comparing Hazel
and Parry in the end |
3 u |
1 u |
The number of sweets that Hazel had in the end is repeated. Make the number of sweets that Hazel had in the end the same. LCM of 1 and 3 is 3.
Number of sweets that Gem had less than Hazel
= 21 u - 5 u
= 16 u
16 u = 80
1 u = 80 ÷ 16 = 5
Number of sweets that Hazel had at first
= 21 u
= 21 x 5
= 105
Answer(s): 105
