Pamela had 60 more candy canes than Min. Pamela used
34 of her candy canes and Min used
12 of her candy canes. In the end, Pamela had 3 times as much as Min. Find the number of candy canes that Min had at first.
| |
Pamela |
Min |
Comparing Pamela
and Parry at first |
60 more |
|
| Before |
4x3 =
12 u |
2 u |
| Change |
- 3x3 =
- 9 u |
- 1 u |
| After |
1x3 =
3 u |
1 u |
Comparing Pamela
and Parry in the end |
3 u |
1 u |
The number of candy canes that Pamela had in the end is repeated. Make the number of candy canes that Pamela had in the end the same. LCM of 1 and 3 is 3.
Number of candy canes that Pamela had more than Min
= 12 u - 2 u
= 10 u
10 u = 60
1 u = 60 ÷ 10 = 6
Number of candy canes that Min had at first
= 2 u
= 2 x 6
= 12
Answer(s): 12
